If theta=pi/(2^n+1) then cos theta cos ...

If `theta=pi/(2^n+1)` then `cos theta cos 2 theta cos 2^(2) theta...... Cos2^(n-1) theta` is equal to

A

`(1)/(2^(n))`

B

`cos theta`

C

2

D

`2^(n)`

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The correct Answer is:

A

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