Given , `cos2^(m)thetacos2^(m+1)theta......cos2^ntheta=(sin2^(n+1)theta)/(2^(n-m+1)sin2^(m) theta) ` where `2^mtheta ne kpi,n,m,k in l` solve the following
`cos2^(3)""(pi)/10cos2^(4)""(pi)/10cos2^(5)""(pi)/10.....cos2^(10)""(pi)/10` is equal to

Options

A. `(1)/(128)`
B. `(1)/(256)`
C. `(1)/(512) "sin" (pi)/(10)`
D. `(sqrt(5)-1)/(512)"sin"(3pi)/(10)`

Answer

B