Calculated spin only magnetic moment of `Cr^(x+)` is 4.9 BM. Find the 'x' value.

Explanation

Magnetic moment `mu=4.9 BM = sqrt(n(n+2))`
Number of unpaired electrons = n= 4
With four unpaired electrons , the configuration is `3d^4 4s^0`
`Cr^(2+)` ion posses 4 unpaired electrons , thus x value is 2.