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The element of 5th period with 5s^(0) 4d...

The element of 5th period with `5s^(0) 4d^(10)` confi guration is

A

Rh

B

Pd

C

Pt

D

Ag

Text Solution

Verified by Experts

The correct Answer is:
B
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In an atom the number of electrons in N - Shell is equal to the number of electrons in K, L and M shells. Answer the question. Write the electronic configuration of the elements. Explanation : K = 1 s^(2) (2) electrons L = 2s^(2) 2p^(6) (8) electrons M = 3s^(2) 3p^(6) 3d^(10) (18) electrons Total (28) electrons N = 4s^(2) 4p^(6) 4d^(10) 4f^(10) (28) electrons To fill 4f^(10) , 1s^(2) , 2s^(2) 2p^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) should be filled Hence , the electronic configuration is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) 4f^(10) .

In an atom the number of electrons in N - Shell is equal to the number of electrons in K, L and M shells. Answer the question. How many electrons are there in its outermost shell ? Explanation : K = 1 s^(2) (2) electrons L = 2s^(2) 2p^(6) (8) electrons M = 3s^(2) 3p^(6) 3d^(10) (18) electrons Total (28) electrons N = 4s^(2) 4p^(6) 4d^(10) 4f^(10) (28) electrons To fill 4f^(10) , 1s^(2) , 2s^(2) 2p^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) should be filled Hence , the electronic configuration is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) 4f^(10) .

In an atom the number of electrons in N - Shell is equal to the number of electrons in K, L and M shells. Answer the question. Which is the outermost shell ? Explanation : K = 1 s^(2) (2) electrons L = 2s^(2) 2p^(6) (8) electrons M = 3s^(2) 3p^(6) 3d^(10) (18) electrons Total (28) electrons N = 4s^(2) 4p^(6) 4d^(10) 4f^(10) (28) electrons To fill 4f^(10) , 1s^(2) , 2s^(2) 2p^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) should be filled Hence , the electronic configuration is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) 4f^(10) .

In an atom the number of electrons in N - Shell is equal to the number of electrons in K, L and M shells. Answer the question. What is the atomic number ? Explanation : K = 1 s^(2) (2) electrons L = 2s^(2) 2p^(6) (8) electrons M = 3s^(2) 3p^(6) 3d^(10) (18) electrons Total (28) electrons N = 4s^(2) 4p^(6) 4d^(10) 4f^(10) (28) electrons To fill 4f^(10) , 1s^(2) , 2s^(2) 2p^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) should be filled Hence , the electronic configuration is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3^(10) 4p^(6) 5s^(2) 4d^(10) 5p^(6) 6s^(2) 4f^(10) .