Home
Class 12
CHEMISTRY
Spin only magnatic moment can be calcula...

Spin only magnatic moment can be calculated by using `mu=sqrt(n(n+2))` where 'n' represents

A

Principal Quantum No

B

Magnetic Quantum No.

C

Number of unpaired electrons

D

Spin Quantum No.

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • D-BLOCK ELEMENTS

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE-2 (ALLOYS)|5 Videos

  • D-BLOCK ELEMENTS

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE-2 (PRMANGANATE AND DICHROMATE)|19 Videos

  • D-BLOCK ELEMENTS

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE-2 (OXIDATION STATES)|15 Videos

  • D - BLOCK ELEMENTS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|50 Videos

  • DILUTE SOLUTIONS

    AAKASH SERIES|Exercise EXERCISE - 1.2|55 Videos

Similar Questions

Explore conceptually related problems

The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where .n. = number of unpaired electrons. B.M. stands for Bohr magneton, a unit of magnetic moment. Which of the following is diamagnetic ?

The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magneticmoment The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where ‘n’ = number of unpaired electrons. B.M stands for Bohr magneton, a unit of magnetic moment. Which of the following has the highest magnetic moment ?

The spin only magnetic moment of Ni^(2+) in aquous solution would be

(A): The spin only magnetic moment of Sc^(+3) 1.73 BM (R) : The spin only magnetic moment (in BM) of an ion is equal to sqrt(n(n+2))

The behaviour of an electron in an atom is described mathematically by a wave function, or orbital. Spin of the electron produce angular momentum equal to S= sqrt(s(s+1)) (h)/(2pi) where S= +1/2 . Total spin of an atom =+ n/2 or h/2 Where n is the number of unpaired electron. The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment the magnetic moment of an atom mu_s sqrt(s(s+1)) (eh)/(2pi mc) = sqrt((n/2)(n/2+1)) (eh)/(2pi mc) s = n/2 implies mu_s = sqrt(n(n+2)) B.M n = number of unpaired electrons 1 B.M. (Bohr magneton) = (eh)/(4pi mc) If magnetic moment is zero the substances is di-magnetic. If an ion of ""_(25)Mn has a magnetic of 3.873 B.M. Then Mn is in which state.

The behaviour of an electron in an atom is described mathematically by a wave function, or orbital. Spin of the electron produce angular momentum equal to S= sqrt(s(s+1)) (h)/(2pi) where S= +1/2 . Total spin of an atom =+ n/2 or h/2 Where n is the number of unpaired electron. The substance which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. The paramagnetism is expressed in terms of magnetic moment the magnetic moment of an atom mu_s sqrt(s(s+1)) (eh)/(2pi mc) = sqrt((n/2)(n/2+1)) (eh)/(2pi mc) s = n/2 implies mu_s = sqrt(n(n+2)) B.M n = number of unpaired electrons 1 B.M. (Bohr magneton) = (eh)/(4pi mc) If magnetic moment is zero the substances is di-magnetic. Which of the following ion has lowest magnetic moement.

n = 2, represents ………….. Shell.

How many +ve integers can be formed using 0,1,2 which are less than 10^n where n is +ve integer

(A) The calculated spin only magnetic moment of Ti^(+2) is 1.73 BM. (R) Number of unpaired electrons in Ti^(+2) is 4.