Explain by drawing a line spectra diagram of the transition between energy levels in an atom.

Explanation

The formula for the wavelength of light emitted from a transition between different atomic states.
`(1)/(lambda_(if))~~R[(1)/(n_(f)^(2))-(1)/(n_(i)^(2))] and n_(f) lt n_(i)`
If `n_(f)=1 and n_(i) =2,3,4...` then the wave number of Lyman series line `alpha, beta, gamma, delta`..... resprectively obtained.
If `n_(f)=2 and n_(i)= 3,4,5`... then wave number of Balmer series line `alpha, beta, gamma, delta,`.... respectively obtained.
If `n_(f)=3 and n_(i)= 4,5,6`... then wave number of Balmer series line `alpha, beta, gamma, delta, `..... respectively obtain If `n_(f)=5 and n_(i)= 6,7,8`... then wave number of pfund series lineed. `alpha, beta, gamma, delta`.,.... respectively obtained.
The spectral line from all the different transitions of the electron in hydrogen atom is shown in figure below.

To remember the short of this series : LAY BAPA BE FUND means
LA = For Lyman `n_(f) = 1`
BA = For Balmer `n_(f) = 2`
PA = For Paschen `n_(f) =3`
BE = For Brackett `n_(f) = 4`
FUND = For Pfund `n_(f)=5`