Home
Class 12
PHYSICS
A 10 kg satellite circles earth once eve...

A 10 kg satellite circles earth once every 2 h in an orbit having a radius of 8000 km. Assuming that Bohr’s angular momentum postulate applies to satellites just as it does to an electron in the hydrogen atom, find the quantum number of the orbit of the satellite.

Text Solution

Verified by Experts

Here mass of satellite m = 10 kg
and radius of orbit `r_(n)`= 8000 km
and time period T = 2 hours =7200s
`h=6.6xx10^(-34)Js`
`rArr` From quantum conditions of angular momentum of Bohr,
`mv_(n)r_(n)=(nh)/(2pi)`
`:.mxx(4pi r_(n)xxm)/(Txxh)`
`:. n=(4xx(3.14)^(2)xx(8xx10^(6))^(2)10)/(7200xx6.64xx10^(-34))`
`:. (25240.576xx10^(12))/(47736xx10^(-34))`
`:.~~5.3xx10^(45)`
Promotional Banner

Topper's Solved these Questions

  • ATOMS

    KUMAR PRAKASHAN|Exercise SECTION-B (Numerical From Textual Exercise)|15 Videos

  • ATOMS

    KUMAR PRAKASHAN|Exercise SECTION-B (Additional Exercises)|13 Videos

  • ATOMS

    KUMAR PRAKASHAN|Exercise TRY YOURSELF |43 Videos

  • ALTERNATING CURRENTS

    KUMAR PRAKASHAN|Exercise SECTION-D MCQs (COMPETITIVE EXAMS)|64 Videos

  • BOARD'S QUESTION PAPER MARCH-2020

    KUMAR PRAKASHAN|Exercise PART-B SECTION -C|4 Videos

Similar Questions

Explore conceptually related problems

A 100 kg satellite circles Earth once every 4 h in an orbit having a radius of 8000 km. Assuming that Bohr's angular momentum postulate applies to satellite just as it does to an electron in the hydrogen atom, find the quantum number of the orbit of the satellite.

The radius of hydrogen atom in its ground state is 5.3xx10^(-11) m. After collision with an electron it is found to have a radius 21.2xx10^(-11) m, then principle quantum number n of the final state of the atom ......

The magnitude of angular momentum, orbit radius and frequency of revolution of elctron in hydrogen atom corresponding to quantum number n are L, r and f respectively. Then accoding to Bohr's theory of hydrogen atom

A satellite of mass M_(S) is orbitting the earth in a circular orbit of radius R_(S) . It starts losing energy slowly at a constant rate C due to friction if M_(e) and R_(e) denote the mass and radius of the earth respectively show that the satellite falls on the earth in a limit time t given by t=(GM_(S)M_(e))/(2C)((1)/(R_(e))-(1)/(R_(S)))

A satellite is to be placed in equatorial geostationary orbit around the earth for communication. (a) Calculate height of such a satellite. (b) Find out the minimum number of satellites that are needed to cover entire earth, so that atleast one satellite is visible from any point on the equator. [M = 6 xx 10^(24) kg, R = 6400 km, T = 24 h, G = 667 x 10-^(11) SI unit]

As you have learnt in the text a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite ? (Take the potential energy at infinity to be zero). Mass of the earth 6.0xx 10^(24(kg) , Radius = 6400 km .

A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence? Mass of the satellite = 200 kg, mass of the earth = 6.0xx 10^(24) kg, radius of the earth = 6.4 xx 10^(6) m, G = 6.67 xx 10^(-11) Nm^(2) kg^( 2)

A satellite orbits the earth at a height of 400 km, above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence ? Mass of the satellite=200 kg, mass of the earth= 6.0xx10^(24) kg, radius of the earth= 6.4xx10(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2) .

A 400 kg satellite is in a circular orbit of radius 2 R_(E) about the Earth. How much energy is required to transfer it to a circular orbit of radius 4R_(E) ? What are the changes in the kinetic and potential energies ?