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A difference of 2.3 eV separates two ene...

A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?

Text Solution

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Here `E=2.3eV. 1 eV=1.6 xx10^(-19)J`
`h=6.625xx10^(-34)Js`
Now E=hv
`:.v=(E)/(h)=(2.3xx1.6xx10^(-19))/(6.625xx10^(-34))`
`:.v=0.55547xx10^(15)`
`:.v=5.6xx10^(14)Hz`
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