How much energy is required to send the electron at infinite distance from the n = 3 orbit in `He^(+)` ?

Options

A. 12.08 eV
B. 6.04 eV
C. 30.2 eV
D. 3.02 eV

Answer

B

Explanation

The energy required `E_(n)=-13.6xx(Z^(2))/(n^(2))eV`
For `He^(+)` n=3 and z=2
`:.E_(He)=(-13.6xx4)/(9)=-6.04 eV`
The total energy should be equal to 6.04 eV given to electron of Het to be zero and hence electron goes infinite distance away.