Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength `lamda`, then what is the quantum number of excited states ?

Options

A. `sqrt((lamdaR-1)/(lamdaR))`
B. `sqrt((lamdaR)/(lamdaR-1))`
C. `sqrt(lamdaR(R-1))`
D. `lamdaR(R-1)`

Answer

B

Explanation

`(1)/(lamda)R[(1)/(1^(2))-(1)/(n^(2))]`
`:.(1)/(lamdaR)=(1)/(1)-(1)/(n^(2))`
`(1)/(n^(2))=1-(1)/(lamdaR)=(lamdaR-1)/(lamdaR)`
`:.n=sqrt((lamdaR)/(lamdaR-1))`