Below are shown the energy levels for a particular atom. A photon with wavelength is emitted when the system transist from the fourth energy level (4E) to the first energy level (E). When the system transist from the `(7)/(3)E` energy level to E energy level photons emitted with wavelength `lamda_(2)`, then `(lamda_(1))/(lamda_(2))=.......`

Options

A. `(9)/(4)`
B. `(4)/(9)`
C. `(3)/(2)`
D. `(7)/(3)`

Answer

B

Explanation

For transition from 4E to E,
`4E-E=(hc)/(lamda_(1))`
`:.3E=(hc)/(lamda_(1))implieslamda_(1)=(hc)/(3E)`
For transition from `(7)/(3)` E to E,
`(7)/(3)E-E=(hc)/(lamda_(2))`
`:.(4E)/(3)=(hc)/(lamda_(2))implieslamda_(2)=(3hc)/(4E):.(lamda_(1))/(lamda_(2))=(4)/(9)`