If the minimum wavelength of Balmer series is `lamda_(1)` and the maximum wavelength of Lyman series is `lamda_(2)`, then ......

Options

A. `lamda_(2)=3lamda_(1)`
B. `lamda_(1)=3lamda_(2)`
C. `lamda_(1)=4lamda_(2)`
D. `lamda_(2)=4lamda_(1)`

Answer

B

Explanation

For minimum wavelength of Balmer series `n=oo`
`(1)/(lamda_(1))=R[(1)/(2^(2))-0]`
`:.lamda_(1)=(4)/(R)" ".........(1)`
For maximum wavelength of Lyman series n = 2
`:.(1)/(lamda_(2))=R[(1)/(1^(1))-(1)/(2^(2))]=R[(1)/(1)-(1)/(4)]=R[(3)/(4)]`
`:.lamda_(2)=(4)/(3R)" "......(2)`
`:.(lamda_(1))/(lamda_(2))=(4xx)/(R)xx(3R)/(4)=3" ":.lamda_(1)=3lamda_(2)`