A hydrogen atom absorbs photon of energy 12.1 eV in ground state, then the change in angular momentum will be ..... Js.

Options

A. `210xx10^(-34)`
B. `2.1xx10^(-34)`
C. `13.3xx10^(-34)`
D. `6.62xx10^(-34)`

Answer

B

Explanation

The electron at n= 1 in the H atom absorb 12.1 eV energy and transist into the `n^(th)` orbit.
`E_(n)=E_(1)=12.1impliesE_(n)=12.1-13.6=-1.51eV`
but `E_(n)=(E_(1))/(n^(2))impliesn^(2)=(E_(1))/(E_(n))=(-13.6)/(-1.51)-=9`
`:.n=3`
`:.` Change in angular momentum,
`=(3h)/(2pi)-(h)/(2pi)=(2h)/(2pi)`
`=(6.62xx10^(-34))/(3.14)`
`=2.1xx10^(-34)Js`