Some energy levels of a molecule are shown the figure. The ratio of the wavelength `r=(lamda_(1))/(lamda_(2))` is given by …………..

Options

A. `r=(3)/(4)`
B. `r=(1)/(3)`
C. `r=(4)/(3)`
D. `r=(2)/(3)`

Answer

B

Explanation

`-E-(-2E)=(hc)/(lamda_(1))`
`:.E=(hc)/(lamda_(1))" "......(1)`
and `-E-(-(4)/(3)E)=(hc)/(lamda_(2))`
`:.(E)/(3)=(hc)/(lamda_(2))" "......(2)`
Dividing equation (2) by equation (1).
`(1)/(3)=(lamda_(1))/(lamda_(2))`
`:.(1)/(3)=r`