In a Rutherford's scattering experiment when a projectile of chargez `Z_(1)`and mass `M_(1)` approaches a target nucleus of `Z_(2)` and mass `M_(2)` the distance of closest approach is `r_(0)`. The energy of the projectile is........

Options

A. directly proportional to `Z_(1), Z_(2)`
B. inversely proportional to `Z_(1)`
C. directly proportional to `M_(1)`
D. directly proportional to `M_(1),M_(2)`

Answer

A

Explanation

The energy of projectile
`(1)/(2)mv^(2)=((Z_(1)e)(Z_(2)e))/(4pi epsi_(0)r_(0))=(Z_(1)Z_(2)e^(2))/(4pi epsi_(0)r_(0))`
So the energy of projectile is proportional to `Z_(1),Z_(2)`