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Consider 3rd orbit of Het (Helium), usin...

Consider 3rd orbit of Het (Helium), using non-relativistic approach, the speed of electron in this orbit will be given `k = 9 xx 10^(9)` constant, Z = 2 and h(Planck's Constant) = `6.6xx10^(-34)JK)`

A

`2.92xx10^(6)m//s`

B

`1.46xx10^(6)m//s`

C

`0.73xx10^(6)m//s`

D

`3.0xx10^(6)m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
For atom like hydrogen
`v=(Z)/(n)xx2.188xx10^(6)`
`:.v=(2)/(3)xx2.188xx10^(6)`
`:.v=1.45866xx10^(6)`
`:.v=1.46xx10^(6)m//s`
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