When an o-particle of mass m moving with velocity v bombards on a heavy nucleus of charge 'Ze', its distance of closest approach from the nucleus depends on m as

Options

A. `(1)/(sqrt(m))`
B. `(1)/(m_(e))`
C. m
D. `(1)/(m)`

Answer

D

Explanation

Initial kinetic energy = Distance from centre -Potential energy
`(1)/(2)mv^(2)=(2Ze^(2))/(4pi epsi_(0)r_(0))`
`:.r_(0)=(2Ze^(2))/(4pi epsi_(0)xx(1)/(2)mv^(2))`
`:. In r_(0) prop (Ze^(2))/(pi epsi_(0)v^(2)m),(Ze^(2))/(pi epsi_(0)v^(2))` constant
`:. r_(0) prop (1)/(m)`