What is ratio of Bohr magneton and nuclear magneton ?

Options

A. `(m_(p))/(m_(e))`
B. `(m_(p)^(2))/(m_(e)^(2))`
C. 1
D. `(m_(e))/(m_(p))`

Answer

A

Explanation

Magnetic moment associated with electrons orbiting around the nucleus is given in terms of Bohr magneton `(mu_(B))`.
`mu_(B)=(eh)/(2m_(e))`
`m_(e)`= electronic mass, e = electronic charge In nuclear physics magnetic moments associated with the spins of protons and neutrons are expressed in nuclear magnetons `(mu_(N))`
`mu_(N)=(eh)/(2m_(p))` where `m_(p)` = mass of proton
`rArr (mu_(B))/(mu_(N))=(m_(p))/(m_(e))`