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The ratio of kinetic energy of the total...

The ratio of kinetic energy of the total energy of an electron of a Bohr orbit of the hydrogen atom is ......

A

`-1`

B

`+1`

C

`-2`

D

`+2`

Text Solution

Verified by Experts

The correct Answer is:
A
Kinetic energy `K=(1)/(8pi epsi_(0))*(Ze^(2))/(r)`
Total energy `E_(n)=-(1)/(8pi epsi_(0))*(Ze^(2))/(r)`
`:.(K)/(E_(n))=-1`
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