The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons stricking the target per second is ...... (Take `e=1.6xx10^(-19)C)`

Options

A. `4xx10^(16)`
B. `2xx10^(16)`
C. `1.6xx10^(16)`
D. `2xx10^(-6)`

Answer

B

Explanation

`I=(Q)/(t)=("ne")/(t)`
`:. n=(It)/(e)=(3.2xx10^(-3)xx1)/(1.6xx10^(-19))`
`:.n=2xx10^(16)`