A molecule A dimerises in 2 molal solution. The boiling point is `100.52^@C`. (`K_b` of water = 0.52, `T_b` of water = `100^@C` ). Find the percentage association.

A solute A dimerizes in water. The boiling point of a 2 molal solution of A is 100. 52^@C . The percentage association of A is ............ (Round off to the Nearest Integer). ["Use "K_b " for water "=0.52 "K kg mol"^(-1) " Boiling point of water "=100^@C]

IF any solution 'A' dimerises in water at 1 atm pressure and the boiling point of this solution is 100.52^@C . IF 2 moles of A is added to 1kg of water and k_b of water is 0.52^@C//molal , calculate the percentage association of A

An aqueous solution boils at 100.50^(@)C .The freezing point of the solution would be (K_(b) for water =0.51^(@)C//m),(K_(f) for water =1.86^(@)C//m ) [no association or dissociation]

The boiling point of a glucose solution containing 12 g of glucose in 100 g of water is 100.34^@C . Boiling point of water is 100^@C . The molal elevation constant of water is

The boiling point of a solution made by dissolving 12.0 g of glucose in 100 g of water is 100.34^(@)C . Calculate the molecular weight of glucose, K_(b) for water = 0.52^(@)C//m .