The molar conductivity of `BaSO_4` at infinite dilution is:
Given : `lamda_m^@(BaCl_2) = 278ohm^(-1)mol^(-1)cm^2 , lamda_m^@(H_2SO_4) = 860ohm^(-1)mol^(-1)cm^2, lamda_m^@(HCl) = 426ohm^(-1)mol^(-1)cm^2`

Compouter the m olar conducitivity of a solution of MgCl_(2) at infinite dilution. Given that lambda_(Mg)^(2+)=106.12ohm^(-1)cm^(2)"mol"^(-1) lambda _(Mg)^(2+)=106.12ohm^(-1)cm^(2)"mol"^(-1)

Calculate the molar conductivity of a solution of NaCl at infinite dilution. Given lambda^(oo)(Na^(+))=50.11 "ohm"^(-1)cm^(2)mol^(-1) lambda^(oo)(Cl^(-))=76.34 "ohm"^(-1)cm^(2)mol^(-1)

Calculte molar conductance at infinite dilution for acetic acid, given A_(m)^(oo)HCI=425 ohm^(-1)cm^(-1),A_(m)^(oo)NaCI=188 ohm^(-1)cm^(-1),A_(m)^(oo)CH_(3)COOHNa=96 ohm^(-1)cm^(-2)mol^(-1)

The specific conducitvity of a saturated solution of AgCI is 3.40 xx 10^6 "ohm"^(-1) cm^(-1) at 25^@C . If lambda_(Ag+) = 62.3 "ohm"^(-1) cm^2 "mol"^(-1) and lambda_(CI-) = 67.7 "ohm"^(-1) cm^2 "mol"^(-1) , the solubility of AgCI at 25^@C is.

From the following molar conductivities at infinite dilution, Lamda_(m)^(@) " for " Al_(2) (SO_(4))_(3) = 858 S cm^(2) mol^(-1) Lamda_(m)^(@) " for " NH_(4)OH = 238.3 S cm^(2) mol^(-1) Lamda_(m)^(@) " for " (NH_(4))_(2)SO_(4) = 238.4 S cm^(2) mol^(-1) Calculate Lamda_(m)^(@) " for " Al(OH)_(3)

The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:

The equivalent conductances of sodium chloride, hydrochloric acid and sodium acetate at infinite dilution are 126.45, 426.16 and 91.0ohm^(-1) cm^(-1)"equiv"^(-1) , respectively, at 25^(@)C . Calculate the equivalent conducatance of acetic acid at infinite dilution. Lambda_(m)^(0)(HCl)="426.16 S cm"^(2)mol^(-1) Lambda_(m)^(0)(NaCl)="126.45 S cm"^(2)mol^(-1) Lambda_(m)^(0)(CH_(3)COONa)="91 S cm"^(2)mol^(-1)

Calculate degree of dissocation of 0.02 M acetic acid at 298K. Given that Lamda_(m) (CH_(3)COOH)= 17.37 S cm^(2) mol^(-1), lamda_(m)^(@) (H^(+)) = 345.8 S cm^(2) mol^(-1), lamda_(m)^(@) (CH_(3)COO^(-)) = 40.2S cm^(2) mol^(-1)

From the following molar conductivities at infinite dilution : wedge_(m)^(@) for Ba(OH)_(2)=457.6Omega^(1)cm^(2)mol^(-1) wedge_(m)^(@) for BaCl_(2)=240.6Omega^(-1) cm^(2)mol^(-1) wedge_(m)^(@) for NH_(4)Cl=129.8 Omega^(-1) cm^(2) mol^(-1) Calculate wedge_(m)^(@) for NH_(4)OH .