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Which of the following is a tautology...

Which of the following is a tautology

A

`((p rarr q) wedge ~ q) rarr p wedgeq`

B

`((p rarr q) wedge ~ q) rarr p `

C

`((p rarr q) wedge ~ q) rarr q `

D

`((p rarr q) wedge ~ q) rarr ~q `

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given statements is a tautology, we will analyze each statement using truth tables. A tautology is a statement that is always true, regardless of the truth values of its components. Let's denote the statements as follows: 1. Statement A: \( p \land q \) 2. Statement B: \( p \implies q \land \neg q \) 3. Statement C: \( p \implies q \) 4. Statement D: \( p \land \neg q \implies p \) We will evaluate each statement step by step. ### Step 1: Construct the truth table for \( p \) and \( q \) | \( p \) | \( q \) | |---------|---------| | T | T | | T | F | | F | T | | F | F | ### Step 2: Evaluate \( p \implies q \) The implication \( p \implies q \) is false only when \( p \) is true and \( q \) is false. | \( p \) | \( q \) | \( p \implies q \) | |---------|---------|---------------------| | T | T | T | | T | F | F | | F | T | T | | F | F | T | ### Step 3: Evaluate \( \neg q \) Negation of \( q \) is true when \( q \) is false. | \( q \) | \( \neg q \) | |---------|---------------| | T | F | | F | T | ### Step 4: Evaluate \( p \implies q \land \neg q \) Now we will evaluate the conjunction \( p \implies q \land \neg q \). | \( p \) | \( q \) | \( p \implies q \) | \( \neg q \) | \( (p \implies q) \land \neg q \) | |---------|---------|---------------------|---------------|------------------------------------| | T | T | T | F | F | | T | F | F | T | F | | F | T | T | F | F | | F | F | T | T | T | ### Step 5: Evaluate \( p \land q \) Now we will evaluate the conjunction \( p \land q \). | \( p \) | \( q \) | \( p \land q \) | |---------|---------|------------------| | T | T | T | | T | F | F | | F | T | F | | F | F | F | ### Step 6: Evaluate \( p \land \neg q \) Now we will evaluate \( p \land \neg q \). | \( p \) | \( \neg q \) | \( p \land \neg q \) | |---------|---------------|-----------------------| | T | F | F | | T | T | T | | F | F | F | | F | T | F | ### Step 7: Evaluate \( p \land \neg q \implies p \) Now we will evaluate the implication \( p \land \neg q \implies p \). | \( p \) | \( \neg q \) | \( p \land \neg q \) | \( p \land \neg q \implies p \) | |---------|---------------|-----------------------|----------------------------------| | T | F | F | T | | T | T | T | T | | F | F | F | T | | F | T | F | T | ### Step 8: Analyze the results Now we will analyze the results of the evaluations: 1. Statement A: \( p \land q \) is not a tautology (not always true). 2. Statement B: \( p \implies q \land \neg q \) is not a tautology (not always true). 3. Statement C: \( p \implies q \) is not a tautology (not always true). 4. Statement D: \( p \land \neg q \implies p \) is a tautology (always true). ### Conclusion The tautology among the statements is **Statement D**: \( p \land \neg q \implies p \). ---
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