Find the value of standard atmospheric pressure of 76cm mercury column in SI unit.

The standard atmosphere pressure is

Calculate the pressure at the bottom of a fresh water lake of depth 10 m. The atmospheric pressure = 76 cm of mercury and the density of mercury = 13.6g*cm^(-3) .

Find out the pressure of 10 cm deep water column.

An air bubble of diameter 1 mm is formed at the bottom of a lake and when it rises to the surface of the water, its diameter becomes 2 mm. If the atmospheric pressure is 760 cm of mercury, then find the depth of the lake. (Density of mercury = 13.6g*cm^(-3) )

A bulb filled with a gas is connected to an open -end manometer. the level of mercury in the arm attached to the gas bulb is 20 cm lower than that in the open. end arm, calculate the pressure of the gas in the bulb in the units of atm and Pa? Consider the atmospheric pressure to be 76 cm Hg.

When an air bubble rises from the bottom of a sea its volume increases to 4 times its initial value. IF the atmospheric pressure is 76 cmHg and the temperatures at the bottom and the surface of the sea are the same. Then what will be the depth of the sea? Density of mercury= 13.6 g.cm^-3 .

The volume of 1 g of water (1 cm^3) becomes 1671 cm^(3) on being converted to steam at standard atmosphere pressure. Find out the work done and rise in internal energy. Given, latent heat of vaporisation of water = 540 cal cdot g^(-1) , the standard atmosphere pressure = 1.013 xx 10^(5) N cdot m^(-2) .