Latent heat of fusion of ice is 80 calore/g, wha does this signify.

The Latent heat of steam is 537 calorie/g, what does this signify.

Latent heat of fusion of ice at 0^(@)C is 80cal/g. calculate the olar entropy change for the fusion process.

A block of ice having mass 6 kg is pulled 50 m horizontally over a surface of ice. The temperature of both the ice is 0^(@)C , coefficient of friction between the surfaces of ice is 0.03 and latent heat of fusion of ice is 80 cal cdot g^(-1) . Calculate the amount of ice that melts.

22320 cal of heat is supplied to 100 g of ice at 0^(@)C . If the latent heat of fusion of ice is 80cal g^(-1) and latent heat of vaporization of water is 540cal g^(-1) , the final amount of water thus obtained and its temperature respectively are

Find out the amount of work done to convert 100 g ice at 0^(@)C to water at 100^(@)C . (Latent heat of fusion of ice = 80 cal cdot g^(-1) , mechanical equivalent of heat = 4.2 J cdot cal^(-1)) .

Latent heat of fusion of tin is 14 cal/g calculate the change in entropy when 10 gm of tin is melted at 232^@C ,

In SI unit the latent heat of fusion of ice is :

5 gm of ice at -10^@C are mixed with 20 gm of water at 39^@C . Will whole of the ice melt? If so, what is the final temperature of the mixture? Specific heat capacity of ice = 0.5 cal gm^-1 "^@C^-1 and latent heat of fusion of ice = 80 cal gm^-1 , specific heat capacity of water = 1cal gm^-1 "^@C^-1 .

At STP if latent heat of fusion of ice is 6 kJ * mol^(-1) , then find out the entropy change of fusion of ice .

What is the amount of work done to convert 40 g of ice at -10^(@)C into steam at 100^(@)C ? Specific heat of ice = 0.5 cal cdot g^(-1) cdot ^(@)C^(-1) , latent heat of fusion of ice =80 cal cdot g^(-1) , latent heat of steam = 540 cal cdot g^(-1), J = 4.2 xx 10^(7) erg cdot cal^(-1) .