Explain briefly the translational kinetic energy of a gas.

What is kinetic energy ?

Find out the temperature at which the average translational kinetic energy of a gas molecule will be equal to the energy gained by an electron on acceleration across a potential difference of 5V, Boltzmann constant, k=1.38 times 2.^-23 J.K^-1 1 ev=1.6 times 10^-19 J .

Statement I: The total translational kinetic energy of all the molecules of a given mass of an ideal gas is 1.5 times the product of its pressure and its volume. Statement II: The molecules of a gas collide with each other and the velocities of the molecules change due to the collision.

Calculate the temperature at which the average translational kinetic energy of the molecules of a gas will be 1/3 rd of that at 180^@C ?

A small sphere of radius r at rest begins to slide down the surface of a hemispherical bowl from the brim of the bowl. When the sphere reaches the bottom of the bowl, what fraction of its total energy will be converted into translational kinetic energy and what fraction into rotational kinetic energy ?

The temperature of a gas is increased from 77^@C to 277^@C . What will be the ratio of the initial and final kinetic energies of the gas molecules?

Calculate the translational kinetic energy and net kinetic energy of an oxygen molecule at 27^@C , where Avogadro number , N=6.023 times 10^23 and Boltzmann constant k= 1.38 times 10^-23 J.K^-1

For which type of gas molecues are the total kinetic energy and translational kinetic energy equal?

Statement I: The root mean square speeds of the molecules of different ideal gases at the same temperature are the same. Statement II: The average translational kinetic energy of molecules of different ideal gas are same at the same temperature.