Derive an expression for critical velocity of satellite. Calculate the acceleration due to gravity at a height of 300 km from the surface of the earth. `M = 6xx10^24kg` R = 6400 km.

Find the acceleration due to gravity at a distance of 20000 km from the centre of the earth.

Find the value of acceleration due to gravity in a mine at a depth of 80 km from the surface of the earth . Radius of the earth = 6400 km .

Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth's surface. M_E = 6 xx 10^24 kg R_E = 6.4 10^6 m

Answer the following questions : What is the acceleration due to gravity at a height h (=radius of the earth) from the surface of the earth ? (g=9.8m/s^2)

Solve the following examples / numerical problems: Find the magnitude of the acceleration due to gravity at the surface of the earth. ( M= 6xx 10^24 kg, R= 6400 km)

The value of acceleration due to gravity will be 1% of its value at the surface of earth at a height of (R_(e )=6400 km)

Show that acceleration due to gravity at height h above the Earth’s surface is g_h = g ((R )/(R+h))^2

Choose the correct alternative and write it along with its allotted alphabet : In the usual notation, the acceleration due to gravity at a height h from the surface of the earth is.....

Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 xx 10^3 km and its mass is 6.4 xx 10^23 kg.

Calculate the K.E, P.E, Total energy and Binding energy of an artificial satellite of mass 2000kg orbiting at a height of 3600 km above the surface of the earth Given: G = 6.67 xx 10^-11 Nm^2//kg R= 6400 km= 6.4 xx 10^6 m M= 6 xx 10^24 kg m = 2000 kg h = 3600 km = 3.6 xx 10^6 m