Home
Class 11
PHYSICS
A man shoutsloudly close to a high wall,...

A man shoutsloudly close to a high wall, he hears an echo. If the man is 40 mfrom the wall, how long after he shouts, will the echo is heard, (speed of sound is `330 m//s`)

Promotional Banner

Topper's Solved these Questions

  • Unit Test 2

    CHETANA PUBLICATION|Exercise EXERCISE|36 Videos
  • UNITS AND MEASUREMENTS

    CHETANA PUBLICATION|Exercise EXERCISE|145 Videos

Similar Questions

Explore conceptually related problems

A man shouts loudly close to a high wall. He hears an echo. If the man is at 40 m from the wall, how long after the shout will the echo be heard? (speed of sound in air = 330 m//s )

A man sets his watch by a whistle that is 2 km away. How much will his watch be in error (speed of sound in air 330 m//s ) ?

Solve the following example: A person standing between two hills fired a gun and heard the first echo after 0.5 s and the second echo after 0.9 s. Find the distance between two hills. (speed of sound in air =340 m//s )

A person standing before a cliff shouts and hears the echo after 1.9s. Find the distance between the person and the cliff. (speed of sound in air=340 m/s )

afires a gun. He heard the echo of the sounds from the first building after 2 seconds and echo i from the second building after 3 seconds. Find the distance between two buildings. (Speed of sound in air = 340 m/s )

A man standing between two parallel cliffsfires a gun and hearstwo echoes of the report, one after 1 s and the other after 4 s. What is the distance between the cliffs if the velocity of sound is 340 m//s .

A person standing between two hills fired a gun heard the first echo after 0.6s and the second echo after 1s. Find the distance between the two hills. (speed of sound in air =340m//s )

If you hear the thunder 20 seconds after you see the flash of lightning, how far from you hasthe lightning occurred? (Speed of sound in air = 340 m/s )

Solve the following example: A person standing before a cliff shouts and hears the echo afte 1.6 s. Find the distance between the person and the cliff. (speed of sound in air= 340 m//s )

A man standing between two cliffs claps his hands and starts hearing series of echoes at interval of one second. Since the speed of sound in air is 340 m//s , the distance between cliffs must be

CHETANA PUBLICATION-Unit Test 3-EXERCISE
  1. The branch of Physics which deals with the production of transmission ...

    Text Solution

    |

  2. The equation shown below is frac(n2 - n1)(R)= frac(n2)(v) - frac(n1)(u...

    Text Solution

    |

  3. What is the magnitude of charge on an electron?

    Text Solution

    |

  4. The product of the magnitude of the charge and the distance between t...

    Text Solution

    |

  5. State Gauss Law

    Text Solution

    |

  6. Define Dispersive Power.

    Text Solution

    |

  7. Calculate the velocity of sound if the frequency of the wave is 4 Hz a...

    Text Solution

    |

  8. Define Total internal reflection

    Text Solution

    |

  9. Define Mirage

    Text Solution

    |

  10. Write a note on periscope. (Diagram essential)

    Text Solution

    |

  11. A man shoutsloudly close to a high wall, he hears an echo. If the man ...

    Text Solution

    |

  12. State law of characteristics of electric lines of force.

    Text Solution

    |

  13. Draw a well labelled diagram for magnifying power of a simple microsco...

    Text Solution

    |

  14. State Coulombs Law and Define relative permitivity.

    Text Solution

    |

  15. For a dense flint glass prism of refracting angle 10^0, Findthe anangu...

    Text Solution

    |

  16. Derive an expression for couple acting on an electric dipole kept in a...

    Text Solution

    |

  17. Explain the effect of change in temperature on the speed of sound in a...

    Text Solution

    |

  18. Derive an expression for electric field intensity of a point on the eq...

    Text Solution

    |

  19. Derive an expression for magnifying power of a compound microscope.

    Text Solution

    |

  20. Derive an expression for apparent frequency when the source is moving ...

    Text Solution

    |