(T=298 K) दिया गया है
`Cu(s)|Cu^(2+) (1.0M)||Ag^(+) (1.0M) |Ag(s) " "E_("सेल")=0.46V`
`Zn(s)|Zn^(2+) (1.0M)||Cu^(2+) (1.0M)|Cu(s) " "E_("सेल")=1.10v`
तब 298 K पर `Zn|Zn^(2+) (0.1M)||Ag^(+) (1.0 M)|Ag" के लिए "E_("सेल")" होगा|"`

Options

A. 1.59V
B. 1.53V
C. 2.53V
D. आकड़े अपर्याप्त होने के कारन गणना नहीं की जा सकती है

Answer

A

Explanation

`E_(Ag^(+)//Ag)^(@)-E_(Cu^(2+)//Cu)^@=0.46V`
`(+) E_(Cu^(2+)//Cu)^@-E_(Zn^(2+)//Zn)^@=1.1V`
`=E_(Ag^(+)//Ag)^@-E_(Zn^(2+)//Zn)^@=1.56V`
`Zn//Zn^(2+) (0.1M)||Ag^(+) (1.0m)|Ag E_("cell")^@=1.56`
`E_("cell")=E_("cell")^@-(0.059)/n log Q`.
Cell reaction
`Zn to Zn^(2+) +2e^(-)`
`+(Ag^(+)+e^(-) to Ag) xx 2`
`=Zn+2Ag^+ to Zn^(2+)+2Ag`
`Q=([Zn^(2+)])/([Ag^(+)]^2)=((0.1))/((1)^2)=0.1`
`rArr E_("cell")=E_("cell")^@-(0.059)/2 log 0.1=1.56-(0.059)/2 xx -1 =1.59V`