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Using the digit 1, 2, 3, 4, 5, 6, and 7,...

Using the digit 1, 2, 3, 4, 5, 6, and 7, a number of 4 different digit is formed find,

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How many four-digit numbers can be formed by using the digits 1, 2, 3, 4, 5, 6, 7 if at least one digit is repeated.

How many four digit numbers divisible by 4 can be made with the digit 1, 2, 3, 4, 5, 6. If the repetition of the digit is not allowed ?

The digits 1, 2, 3, 4, 5, 6, 7, 8, and 9 are written in random order to form a nine digit number.Let p be the probability that this number is divisible by 36, find 9p.

How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that  (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed?

Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even?

Three-digit numbers are formed using the digits 0,1, 2, 3, 4, 5 without repetition of digits. If a number is chosen at random, then the probability that the digits either increase or decrease, is

How many 6-digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10 and no digit is repeated ?

Let an denote the number of all n-digit positive integers formed by the digits 0, 1 or both such that no consecutive digits in them are 0. Let b_n = the number of such n-digit integers ending with digit 1 and c_n = the number of such n-digit integers ending with digit 0. The value of b_6 , is

How many 4-digit number can be formed with the digit 1, 2, 3, 4, 6 and 8 if repetition of digits is not allowed.

Statement-1: A 5-digit number divisible by 3 is to be formed using the digits 0,1,2,3,4,5 without repetition, then the total number of ways this can be done is 216. Statement-2: A number is divisible by 3, if sum of its digits is divisible by 3.