A stone is throuwn in a vertically upward direction with a velocity of `5 ms ^(-1).` If the acceleration of the stone during its motion is `10 ms ^(-2)` in the downword direction, what will be the height attained by the stone and how much time will it take to reach there ?

Explanation

Here, `u = 5 ms ^(-1), a =- 10 ms ^(-2)..`
(Because the stone is moving in the upward direction).
`u =0…` at the highest point.
`v + u + at`
`therefore 0 = 5 + (1-10)t therefore 10 t =5 therefore t =0.5 sec`

The stone will reach the height of `1.25 m ` and the time required is `0.5 sec. `