A car accelerates uniformly from `18 km h^(-1 )`to `36 km h^(-1)` in 5 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time.

Explanation

Here, `u = 18 km h ^(-1) = 5 ms ^(-1)`
` v = 36 km h ^(-1) = 10 ms ^(-1)`
`(i)a = (v - u)/(t)`
`=(10 ms ^(-1) - 5 ms ^(-1))/( 5s)= 1 ms ^(-2)`
(ii) `s = ut + 1/2 at ^(2)`
`= ( 5m s ^(-1)) xx (5s ) + 1/2 xx (1m s ^(-2)) xx (5s) ^(2)`
`= 25 m + 12.5 m`
`= 37. 5m`
The acceleration of the car is `1 ms ^(-2)` and the distance covered is `37.5 m.`