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The brakes applied to a car produce an a...

The brakes applied to a car produce an acceleration of `6 ms^( 2)` in the opposite direction to the motion. If the car takes 2s to stop after the application of brakes, calculate the distance it travels during this time.

Text Solution

Verified by Experts

Here, `a =- 6 ms ^(-2),t =2 s and v =0 ms ^(-1) v =u +at`
`0= u + (-6 ms ^(-2)) xx 2s`
` or u = 12 ms ^(-1)`
`s = ut + (1)/(2) at ^(2)`
`= (12 ms ^(-1)) xx (2s) + (1)/(2) (- 6 ms ^(-2)) xx (2s )^(2)`
`= 24 m-12 m= 12 m`
Thus, the car will travel 12 m before it stops after the application of brakes.
Can you now appreciate why drivers are cautioned to maintain some distance between vehicles while travelling on the road ?
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