`intsecx/(secx+tanx)dx`

intsecxlog(secx+tanx)dx

Evaluate int secx/log(secx+tanx)dx

int((secx)/(secx-tanx))dx equals

Evaluate int(secx)/((secx+tanx)) dx .

int(1)/(secx+tanx)dx=

int(tanx)/(secx+tanx)dx=

intsinxlog(secx+tanx)dx=

Evaluate int(tanx)/(secx+tanx)dx

The integral int (sec^2x)/(secx+tanx)^(9/2)dx equals to (for some arbitrary constant K ) (A) -1/(secx+tanx)^(11/2){1/11-1/7(secx+tanx)^2}+K (B) 1/(secx+tanx)^(11/2){1/11-1/7(secx+tanx)^2}+K (C) -1/(secx+tanx)^(11/2){1/11+1/7(secx+tanx)^2}+K (D) 1/(secx+tanx)^(11/2){1/11+1/7(secx+tanx)^2}+K

intsecx/(b+atanx)dx