Prove that `(A nn B)=A'uu B'` where A ,B be two sets.

Prove that A uu(A nn B)=A

Verify that (A nn B)'=A'uu B' ,where A={2,3, 4, 5, 6} , B={3,6,7,8} are subsets of U={1,2,3,4,5,6,7,8}

Verify that (A nn B)'=A'uu B ,where A={2,3 ,4,5,6},B={3,6,7,8} are subsets of U={1,2,},{3,4,5,6,7,8}

Prove A nn B=A and A uu B=A rArr A=B

If A, B are two sets, prove that AuuB=(A-B)uu(B-A)uu(AnnB) . Hence or otherwise prove that n(AuuB)=n(A)+n(B)-n(AnnB) where, n(A) denotes the number of elements in A.

If U={2,3,5,7,9} is the universal set and A={3,7},B={2,5,7,9}, then prove that: (A uu B)'=A'nn B'( ii) (A uu B)'=A'uu B'

A uu B = A nn B iff :

If A and B are any two events such that P(A)=(2)/(5) and P(A nn B)=(3)/(20) then the conditional probability P(A|(A'uu B')) where A' denotes the complement of A is equal to

If A, B and C are three sets such that A nn B = A nn C and AuuB = A uu C , then

A = (A nn B) uu (AB) and A uu (BA) = (A uu B)