The distance of a point on the ellipse x...

The distance of a point on the ellipse `x^(2) + 3y^(2) = 6` from its centre is 2. Find the eccentric angle of the point.

Verified by Experts

The correct Answer is:

`pi//2`

Similar Questions

Explore conceptually related problems

The distance of a point on the ellipse x^(2)//6+y^(2)//2=1 from the centre is 2. The eccentric angle of the point is

The dist. of a point P on the ellipse (x^(2))/(12)+(y^(2))/(4)=1 from centre is sqrt(6) then the eccentric angle of Pis

The points on the ellipse 2x^(2)+3y^(2)=6 whose eccentric angles differ by two right angles is

The maximum distance of the the normal to the ellipse (x^(2))/(9)+(y^(2))/(4)=1 from its centre is

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)

The equation of the normal to the ellipse x^(2)//16+y^(2)//9=1 at the point whose eccentric angle theta=pi//6 is

If pi+theta is the eccentric angle of a point on the ellipse 16x^(2)+25y^(2) = 400 then the corresponding point on the auxiliary circle is

The equation of the normal to the ellipse (x^(2))/(4)+(y^(2))/(2)=1 at the point whose eccentric angle is (pi)/(4) is

Show that the maximum distance of centre of the ellipse x^(2)/a^(2)+y^(2)/b^(2) = 1 from a normal to the ellipse is (a - b).