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The tangent at a point P(theta) to the e...

The tangent at a point `P(theta)` to the ellipse `x^2/a^2+y^2/b^2=1` cuts the auxilliary circle at Q and R. If QR subtend a right angle at C (centre) then show that `e=1/sqrt(1+sin^2 theta)`

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The correct Answer is:
`(1+sin^2 theta)^(-1/2)`
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