Home
Class 11
MATHS
The shortest distance between the lines...

The shortest distance between the lines `vecr = (2 veci -vecj - veck) + lamda ( 2 veci + vecj + 2 veck) and vecr = (veci + 2 vecj + veck) + mu ( veci - vecj + veck) ` is

A

`3//sqrt2`

B

`3sqrt2`

C

`2//sqrt3`

D

`sqrt2//3`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the shortest distance between the following pair of parallel lines whose equation are: vecr = veci + 2 vecj + 3veck + lamda (veci - vecj + veck) and vecr = 2 veci - vecj - veck + mu (-veci + vecj - veck) is

The shortest distance between the line vecr = (1-t) veci + (t-2) vecj + (3-2t) veck and vecr = (s + 1) vect + (2s -1) vecj - (2s + 1) veck is

The shortest distance between the line y-x =1 and the curve x=y^2 is

The distance between the line vecr = 2 hati - 2 hatj + 3 hatk + lamda ( hati - hatj + 4 hatk) and the plane vecr. (hati + 5 hatj + hatk) = 5 is

If veca=2veci-vecj+veck and vecb=veci-3vecj-5veck , then find |vecaxxvecb| .

The distance between the line vecr = 2hati - 2hatj + 3hatk + lambda (hati-hatj + 4hatk) and the plane vecr. (hati + 5hatj + hatk) = 5 is

Find the angle between the vectors veci+2vecj+3veck and 3veci-vecj+2veck