Home
Class 11
MATHS
Equation of a line in the plane pi -= 2x...

Equation of a line in the plane `pi -= 2x - y + z -4=0` which is perpendicular to the line l whose equation is `(x-2)/(1) = (y-2)/(-1) = (z-3)/(--2)` and which passes through the point of intersection of l and `pi` is

A

`(x-2)/(1) = (y -1)/(5) = (z-1)/(-1)`

B

`(x-1)/(3) = (y-3)/(5) = (z-5)/(-1)`

C

`(x -2)/(2) = (y+1)/(-1) = (z+1)/(1)`

D

`(x -2)/(2) = (y-1)/(-1) =(z-1)/(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Equation of the plane perpendicular to the line (x)/(1)=(y)/(2)=(z)/(3) and passing through the point (2,3,4) is

The equation of the straight line which is perpendicular to the line 5x-2y =7 and passing through the point of intersection of the lines 2x + 3y-1 =0 and 3x + 4y -6 = 0 is

The equation of the straight line perpendicular to the straight line 3x+2y=0 and passing through the point of intersection of the lines x+3y-1=0 and x-2y+4=0 is

The equation to the plane which passes through the z-axis and is perpendicular to the line (x-a)/( cos alpha ) = (y +2)/(sin alpha ) = (z -3)/(0) is

The equation of the straight line perpendicular to 5x-2y=7 and passing through the point of intersection of the lines 2x+3y=1 and 3x+4y=6 is

Equation of a plane through the line (x-1)/(2) = (y-2)/(3) = (z-3)/(4) and parallel to a coordinate axis is