Home
Class 11
MATHS
An angle is increasing at a constant rat...

An angle is increasing at a constant rate. The rate of increase of tan when the angle is `pi//3` is

A

4 C

B

6 C

C

8 C

D

2 C

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • RATE MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - 1) (LEVEL - 1) (STRAIGHT OBJECTIVE TYPE QUESTION)|43 Videos
  • PROPERTIES OF VECTORS

    AAKASH SERIES|Exercise PRACTICE EXERCISES|55 Videos
  • RATE OF CHANGE

    AAKASH SERIES|Exercise Advanced Subjective Type Questions|22 Videos

Similar Questions

Explore conceptually related problems

The volume of a ball increases at 2pic.c//sec . The rate of increase of radius when the volume is 288pi c.cms is

The correct order of increasing bond angles is

The correct increasing order of bond angle is

The radius of the base of a cone is increasing at the rate of 3 cm/min and altitude is decreasing at the rate of 4 cm/min. The rate of change of lateral surface when the radius is 7 cm and altitude is 24 is

The volume of a sphere is increasing at the rate of 1200 c.cm/sec. The rate of increase in its surface area when the radius is 10 cm is

If the volume of a spherical ball is increasing at the rate of 4pi cc/sec, then the rate of increases of its radius (in cm/sec), when the volume is 288pi cc.

The slant height of a cone is fixed as 7 cm. If the rate of increase in tis height os 0.3 cm/sec, then the rate of increase of volume when height 4 cm is

The increase in rate constant of a reaction is more when the temperature increases from

The side of an equilateral triangle increases at the uniform rate of 0.05 cm/sec. The rate of increase in the area of the triangle when the side is 20 cm is

AAKASH SERIES-RATE MEASUREMENT-PRACTICE SHEET (EXERCISE - 1) (LEVEL - 1) (STRAIGHT OBJECTIVE TYPE QUESTION)
  1. An angle is increasing at a constant rate. The rate of increase of tan...

    Text Solution

    |

  2. If a particle moves alonga straight line by S = 4t^(2) - 8t + 3 and th...

    Text Solution

    |

  3. The rate of change of sin t is n, then the rate of change of tan t is

    Text Solution

    |

  4. A particle moves along a straight line according to the equation s = 8...

    Text Solution

    |

  5. An angle theta through which a pulley turns with time 't' is completed...

    Text Solution

    |

  6. A particle moves along a line by s = (t^(3))/(3) - 3t^(2) + 8t then th...

    Text Solution

    |

  7. A particle 'p' moves along a straight line away from a point 'O' obeyi...

    Text Solution

    |

  8. If the rate of change of sine and tangent of the same angle are equal ...

    Text Solution

    |

  9. If the displacement in time t of a particle is given by s = ae^(t) + b...

    Text Solution

    |

  10. If the distance S travelled by a particle in time t is given by s = t^...

    Text Solution

    |

  11. The displacement of a particle in time 't' is given by S = t^(3) - t^(...

    Text Solution

    |

  12. A particle moves in a straight line according to the law v^(2) = 4a (x...

    Text Solution

    |

  13. The distance moved by the particle in time 't' is given by S = t^(2) -...

    Text Solution

    |

  14. A particle moves along the X-axis with velocity v = (dx)/(dt)=f(x) the...

    Text Solution

    |

  15. If the distance travelled by a particle is x = sqrt(pt^(2) + 2qt + r...

    Text Solution

    |

  16. If a particle moves along a line by S = sqrt(1 + t) then its accelerat...

    Text Solution

    |

  17. A particle moves on a line according to the law s = at^(2) + bt + c. I...

    Text Solution

    |

  18. A particle velocity v at time is given by v = 2e^(2t) cos(pi t)/(3). T...

    Text Solution

    |

  19. Each side of an equilateral triangle expands at the rate of 2 cm/sec. ...

    Text Solution

    |

  20. A variable triangle ABC is inscribed in a circle of diameter x units. ...

    Text Solution

    |

  21. An aeroplane is flying horizontally at an altitude of 3000 ft directly...

    Text Solution

    |