Home
Class 11
MATHS
Let f(x)=ax^(2)+bx+c,a,b,c in Randa ne0 ...

Let `f(x)=ax^(2)+bx+c,a,b,c in Randa ne0` suppose `f(x)gt0` for all `x in R` Let `g(x)=f(x)+f(x)+f'(x)` then

A

`g(x)gt0AA x in R`

B

`g(x)lt0AA x in R`

C

`g(x)=0` has no real complex roots

D

sum of the roots of g(x)=0 is -3 if `omega,omega^(2)` are roots of f(x)=0 where `omega` is the cube roots of unity

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
Promotional Banner

Topper's Solved these Questions

  • MAXIMA AND MINIMA

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE -II) (MATRIX MATCHING TYPE QUESTIONS)|3 Videos
  • MAXIMA AND MINIMA

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE -II) (LINKED COMPREHENSION TYPE QUESTIONS)|5 Videos
  • MAXIMA AND MINIMA

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE -II) (STRAIGHT OBJECTIVE TYPE QUESTIONS)|54 Videos
  • MAXIMA & MINIMA

    AAKASH SERIES|Exercise EXERCISE-III|35 Videos
  • MEAN VALUE THEOREMS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-I (LEVEL-II (MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS ) )|2 Videos

Similar Questions

Explore conceptually related problems

Let f(x) = ax^(3) + bx +c . Then when f is odd,

Let f(x)=x^(2)+ax+b , where a, b in R . If f(x)=0 has all its roots imaginary, then the roots of f(x)+f'(x)+f''(x)=0 are

Theorem: Let f(x)=ax^(2)+bx+c be a quadratic function. If a gt0 then f(x) has minimum value at x=(-b)/(2a) and the minimum value =(4ac-b^(2))/(4a) .

Let f(x) = x^2 + ax + b , where a, b in RR . If f(x) =0 has all its roots imaginary , then the roots of f(x) + f'(x) + f(x) =0 are :

Theorem : Let f(x)=ax^(2)+bx+c be a quadratic function. If a gt 0 then f(x) has minimum value at x =(-b)/(2a) and the minimum value = (4ac -b^(2))/(4a)

Let f(x) = x^(2) and g(x) = sin x for all x in R. Then the set of all x satisfying (fogogog)(x) = (gogof)(x), where (fog)(x) = f(g(x)), is

If f (x) = ax ^(2) + bx + c then find Lt _(x to 5) (f (x) - f (5))/(x-5)

Theorem : Let f(x)=ax^(2)+bx+c be a quadratic function. If a lt 0 then f(x) has maximum value at x=(-b)/(2a) and the maximum value =(4ac-b^(2))/(4a)

Theorem: Let f(x)=ax^(2)+bx+c be a quadratic function. If a lt 0 then f(x) has maximum value at x=(-b)/(2a) and the maximum value =(4ac-b^(2))/(4a)