A wire of length 'a' is cut into two parts which are bent in the form a square and a circle. Show that the least value of the sum of the areas so formed is `(a^2)/(4(pi+4))`.

Options

A. `(a^(2))/(pi+4)`
B. `(a^(2))/(2(pi+4))`
C. `(a^(2))/(3(pi+4))`
D. `(a^(4))/(4(pi+4))`

Answer

D