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If f(x) = a log |x| + bx^(2) + x has ext...

If f(x) = a log |x| + `bx^(2)` + x has extreme values at x = -1 and x = 2 , then the ordered pair (a,b) =

A

a=2, b =-1

B

`a=2,b=-(1)/(2)`

C

`a=-2,b=(1)/(2)`

D

`a=2,b=1//2`

Text Solution

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The correct Answer is:
B
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