`square ABCD` is a rectangle. Taking AD as a diameter, a semicircle AXD is drawn which intersects the diagonal BD at X. If AB=12 cm, AD=9 cm, then find values of BD and BX.

In trapezium ABCD side AB|| side DC, diagonals AC and BD intersect In point O. If AB=20, DC=6, OB=15 then find OD.

In DeltaABC Seg BD bisects /_ABC . If AB=x, BC=x+5, AD=x-2, DC=x+2 , then find the value of x .

In an equilateral triangle ABC, If ADbotBC, B-D-C and AB = 12 cm, then the value of AD is

In the adjoining figure, seg AB is a diameter of a circle with centre O. Bisector of inscribed /_ACB intersects circle at point D. prove: seg AD~=seg BD

In square ABCD , seg AD|| seg BC. Diagonal AC and digonal BD intersect each other in point P. Then show that (AP)/(PD)=(PC)/(BP) .

Draw a Delta ABC . 1. Bisect angleB and name the point of intersection of AC and the angle bisecto as D. 2. Mesure the sides. AB= square cm , BC = square cm, AD = square cm, DC = square cm 3. Find rations (AB)/(BC) and (AD)/(DC) . 4. You will find that both the rations are almost equal. 5. Bisect remaining angles of the triangle and find the ration as above. Verify that the ratios are equal.

Length of a tangent segment drawn from a point which is at a distnace 12.5 cm from the centre of a circle is 12cm , find the diameter of the circle.