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Select the correct option from the given alternatives. If `A = [[3,2],[1,4]]` then `A(adjA) = ` i] `[[10,0],[0,10]]` ii] `[[0,10],[10,0]]` iii] `[[10,1],[1,10]]` iv] `[[1,0],[0,1]]`

A

`[[10,0],[0,10]]`

B

`[[0,10],[10,0]]`

C

`[[10,1],[1,10]]`

D

`[[1,0],[0,1]]`

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