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If `x= a(costheta + sintheta), y= a(sintheta + costheta)`, then `(d^2y)/(dx^2)` at `theta` = `pi/4` .............

A

`frac{8 `sqrt 2}{a`pi`}

B

- `frac{8 `sqrt 2}{a`pi`}

C

`frac{a`pi`}{8 `sqrt 2}

D

`frac{4 `sqrt 2}{a`pi`}

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