Let’s calculate the quantities of Assam tea and Darjeeling tea out of 25 kg in casket. if these are blended in the ratio of measurement 3 : 2.

1 mole N_2 and 3 moles of H_2 are taken in a 4 litre flask. If 0.25% of N_2 is converted to NH_3 at equilibrium and the reaction is N_2(g)+3H_2(g)iff2NH_3(g) . Then calculate the value of K_c under that condition. Prove that for the reaction aA_2(g)+bB_2(g)iffcAB(g) the value of the ratio K_p/K_c is 1 when a+b=c.

In a certain year, Vivekanda Youth Library received a Govt. grant of Rs. 74,350 and collected a subscription or Rs. 4,350. Also, they got Rs. 1300 by selling old papers etc. If the entire money is spent on buying new books, for binding of old books and paying salary to employees in the ratio of 15 : 3 : 2 . Now let's calculate for how much new book were bought.

Einstein established the idea of photons on the basis of Planck's quantum theory. According to his idea, the light of frequency f or wavelength lamda is infact a stream of photons. The rest mass of each photon is zero and velocity is equal to the velocity of light (c) = 3 xx 10^(8) m.s^(-1) . Energy, E = hf, where h = Planck's constant = 6.625 xx 10^(-34)J.s . Each photon has a momentum p = (hf)/(c) , although its rest mass is zero. The number of photons increase when the intensity of incident light increases and vice-versa. On the other hand, according to de Broglie any stream of moving particles may be represented by progressive waves. The wavelength of the wave (de Broglie wavelength) is lamda = (h)/(p) , where p is the momentum of the particle. When a particle having charge e is accelerated with a potential difference of V, the kinetic energy gained by the particle is K= eV. Thus as the applied potential difference is increased, the kinetic energy of the particle and hence the momentum increase resulting in a decrease in the de Broglie wavelength. Given, charge of electron, e = 1.6 xx 10^(-19)C and mass = 9.1 xx 10^(-31) kg . Two stationary electrons are accelerated with potential difference V_(1) and V_(2) respectively such that V_(1) : V_(2) = n . The ratio of their de Broglie wavelength

If 64 water filled buckets of equal measure are taken out from a cubical water fiUed tank, then 1/3 rd of water remains in the tank. If the length of one edge of the tank is 1 ·2 m, then calculate the quantity of water that can be hold in each bucket ?

A physical quantity P is related to four observables a, b, c and d as follows: P = (a^(3)b^(3))/(sqrt(cd)) The percentage errors of measurement in a,b, c and d are 1%, 3%, 4%, and 2% respectively. What is the percentage error in the quantity P? If the value of P calculated using the given relation turns out to be 3.763, to what value should the result be rounded off?

A physicaI quantity P is reIated to four observabIes a, b, c and d as foIIows: P = a^(3)b^(2)//(sqrt(cd)) The percentage errors of measurement in a,b, c and d are 1%, 3%, 4% and 2%, respectiveIy. What is the percentage error in the quantity P? If the vaIue of p caIcuIated using the above reIation turns out to be 3.763 to what vaIue shouId you round off the resuIt?