The horizontal component of the earth’s magnetic field at a given place is `0.4 xx 10^-4 Wb//m^2` and angle of dip is `30^@`. Calculate the value of the total Intensity of earth's magnetic field.

The horizontal component of the earth’s magnetic field at a given place is 0.4 xx 10^-4 Wb//m^2 and angle of dip is 30^@ . Calculate the value of vertical component

The horizontal component of earth's magnetic field at a place is 0.25 x 10^-4 T and the resultant mag netic field is 0.5 x 10^-4 T. Find the dip and the vertical component of the earth's magnetic field

The elements of earth.s magnetic field at a place are declination, dip and horizontal intensity. The vertical component of earth.s magnetic field at a given place is sqrt 3 times its horizontal component. If total intensity of earth.s magnetic field at the place is 0.4 G find the value of horizontal component of earth.s magnetic field.

The elements of earth’s magnetic field at a place are declination, dip and horizontal intensity.The vertical component of earth’s magnetic field at a given placeis , sqrt3 times its horizontal,component. If total intensity of earth’s magnetic field at the place Is 0.4G, find the value of horizontal component of earth’s magnetic field.

Where on earth’s surface is the value of vertical component of Ihe earth’s magnetic field zero ?