The percentage error in the mass and speed are 2% and 3% respectively. What is the maximum error in kinetic energy calculated using these quantities?

Explanation

`(Delta m)/( m) x 100 = 2% , (Delta upsilon)/( upsilon) xx 100 = 3% `
Kinetice energy. `E= (1)/(2) m upsilon^(2) `
Maximum error in kinetic energy
`(Delta E)/( E) xx 100 = (Delta m)/( m) xx 100 + 2 (Delta upsilon)/( upsilon) xx 100`
Maximum error in kinetic energy
`= 2 % + 2 xx 3% = 2% + 6% = 8%`