The mass of 1.2 `cm^3` of a certain substance is 5.74g. Calculate its density with due regard to significant figures.

Explanation

Mass, `m=5.74g , "volume", v=1.2 cm^(3)`
density , `d= (m)/(v) = (5.74g)/( 1.2 cm^3)`
`5.74` has significant digits and 1.2 has two significant digits. no need for rounding off.
`therefore d= (5.74)/( 1.2) = 4.783333.`
This is to be rounded off to two significant digits. The density of the given substance is `4.783=4.8"gcm"^(-5)`